Combined Gas Law Calculator

The law combines Boyle's, Charles's and Gay-Lussac's laws. 10 liters of gas at 1 pressure unit and 300 kelvin, compressed to 2 units and warmed to 350 kelvin, occupies about 5.83 liters. Use it to predict how a balloon, a tire or a sealed container responds to changes in temperature and pressure.

Doubling the pressure halves the volume at constant temperature, and heating raises volume or pressure.

Combined Gas Law Calculator: inputs

Calculated result
Final volume (L)5.8
P × V ÷ T (constant)0.0333

Combined Gas Law Calculator: Initial pressure (any unit) sensitivity

Combined Gas Law Calculator: Initial pressure (any unit) and Final volume (L)5 calculations vary the “Initial pressure (any unit)” input while holding the other entered inputs constant.0.84.70.95.315.81.16.41.27

Combined Gas Law: formula

P₁ × V₁ ÷ T₁ = P₂ × V₂ ÷ T₂, so V₂ = P₁ × V₁ × T₂ ÷ (T₁ × P₂), with temperatures in kelvin

OpenStax Chemistry: gas

Enter the initial pressure, initial volume, initial temperature in kelvin, final pressure and final temperature. Pressures can be in any unit as long as both use the same one. Temperatures must be in kelvin, so add 273.15 to Celsius values.

The law states that pressure times volume divided by temperature is constant for a fixed amount of gas, so the final volume follows from the other five values.

Combined Gas Law: worked example

Initial pressure (any unit)1
Initial volume (L)10
Initial temperature (K)300
Final pressure (same unit)2
Final temperature (K)350
Final volume (L)5.8
P × V ÷ T (constant)0.0333

It applies to an ideal gas with a fixed amount, and real gases deviate at high pressure or low temperature. Gas leaking or added changes the amount. Using Celsius instead of kelvin is the most common mistake.

Phase changes such as condensation break the law.

Combined Gas Law: changing Initial pressure (any unit)

Initial pressure (any unit)Final volume (L)P × V ÷ T (constant)
0.84.70.0267
0.95.30.0300
1 (example)5.80.0333
1.16.40.0367
1.270.0400

Combined Gas Law: compare input ranges

InputTested fromToFinal volume (L): low inputFinal volume (L): high inputSwing
Initial temperature (K)2703306.55.31.2 (20%)
Final pressure (same unit)1.82.26.55.31.2 (20%)
Initial pressure (any unit)0.91.15.36.41.2 (20%)
Initial volume (L)9115.36.41.2 (20%)
Final temperature (K)3153855.36.41.2 (20%)

Combined Gas Law: individual input comparisons

InputValueFinal volume (L)P × V ÷ T (constant)
Initial pressure (any unit)0.84.70.0267
0.95.30.0300
15.80.0333
1.16.40.0367
1.270.0400
Initial volume (L)84.70.0267
95.30.0300
105.80.0333
116.40.0367
1270.0400
Initial temperature (K)2407.30.0417
2706.50.0370
3005.80.0333
3305.30.0303
3604.90.0278
Final pressure (same unit)1.67.30.0333
1.86.50.0333
25.80.0333
2.25.30.0333
2.44.90.0333
Final temperature (K)2804.70.0333
3155.30.0333
3505.80.0333
3856.40.0333
42070.0333

Combined Gas Law: combined input changes

Initial pressure (any unit) / Initial volume (L)81012
0.83.74.75.6
0.94.25.36.3
14.75.87
1.15.16.47.7
1.25.678.4

Combined Gas Law: which assumptions move the result?

Combined Gas Law: Final volume (L) as Initial temperature (K) changesFinal volume (L) starts at 7.3. Moving Initial temperature (K) from 240 to 360 changes it to 4.9, with Initial pressure (any unit) 1; Initial volume (L) 10; Final pressure (same unit) 2; Final temperature (K) 350 kept fixed.2407.32706.53005.83305.33604.9
Chart quantityDisplayed settings
Initial temperature (K)240 → 360
Final volume (L)7.3 → 4.9
Initial pressure (any unit)1
Initial volume (L)10
Final pressure (same unit)2
Final temperature (K)350
Combined Gas Law: Final volume (L) as Final pressure (same unit) changesFinal volume (L) starts at 7.3. Moving Final pressure (same unit) from 1.6 to 2.4 changes it to 4.9, with Initial pressure (any unit) 1; Initial volume (L) 10; Initial temperature (K) 300; Final temperature (K) 350 kept fixed.1.67.31.86.525.82.25.32.44.9
Chart quantityDisplayed settings
Final pressure (same unit)1.6 → 2.4
Final volume (L)7.3 → 4.9
Initial pressure (any unit)1
Initial volume (L)10
Initial temperature (K)300
Final temperature (K)350

Combined Gas Law: values and definitions

Quantity and definitionValue used
Initial pressure (any unit)1
Initial volume (L)10
Initial temperature (K) — Kelvin: add 273.15 to a Celsius reading.300
Final pressure (same unit)2
Final temperature (K)350
Final volume (L)5.8
P × V ÷ T (constant)0.0333

Combined Gas Law: half and double Initial temperature (K)

Initial temperature (K)Final volume (L)
15011.7
3005.8
6002.9

Common error: Applying it when gas is added or leaks out. The law holds only for a fixed amount of gas, and a changing amount needs the ideal gas law instead.

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The combined gas law joins Boyle's, Charles's and Gay-Lussac's laws: pressure times volume divided by temperature stays constant for a fixed amount of gas. Raise the pressure from 1 to 2 and the temperature from 300 to 350 kelvin, and 10 liters shrink to about 5.83. Pressure pushes the volume down, and the temperature pushes it up, and the two effects multiply.

Use kelvin for both temperatures and the same pressure unit on both sides. A Celsius reading in the formula gives a result that is far off.

Convert temperatures on the temperature converter, pressures on the pressure converter, and volumes on the volume converter. The density and molarity calculators cover related lab quantities, and the percent yield and dilution pages support chemistry work.

Why must temperature be in kelvin?

Because the gas laws are proportional to absolute temperature, and Celsius and Fahrenheit have zero points that do not correspond to zero energy.

Does it work for real gases?

Approximately, at moderate pressures and temperatures. At high pressure or near condensation, real gases deviate from ideal behavior.

What is the combined gas law?

It says that pressure times volume divided by temperature stays constant for a fixed amount of gas, combining Boyle's, Charles's and Gay-Lussac's laws.